Question

f 5 and 6 are the zeros of x2 - (a+1)x +b then (a) a = -10 , b = -30 (b) a =10 , b = 30 (c) a =-10, b=30 (d) a=10,b=-30​

Answer 1

Answer:

As the given equation is

x^2-(a+1)x+b=0

The roots of the given equation are 5 &6.

According to formula-

x^2-(C+D)x+CD=0

Here

x^2-(6+5)x+6*5=0

x^2-11x+30=0

Then

-(a+1)=-11,b=30

a+1=11,b=30

a=11-1=10,b=30

Answer-(b)a=10, b=30