f 6 man and 8 boys can do a piece of work in 10 days, while 26 men and 48 boys can do the same work in 2 days, then what is the time taken by 1 men and 20 boys in doing the same type of work ?
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Step-by-step explanation:
B) 4 days
Description for Correct answer:
(6m+8b)×10 days
=(26m+48b)×2 days
[m1×t1×d1w1=m2×t2×d2w2]
30m+40b=26m+48b
4m = 8b
m = 2b
mb=21
1m (work) = 2 units/day
1b (work) = 1 units/day
Hence,
Total work
=(6×2+8×1)×10
=200 units
Required Time
(15m+20b)
=200(15×2+20×1)=20050=4 days
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