Question

F 60 ml of water contains 12% of chlorine, how much water must be added in order to create a 8% chlorine solution?

Answer 1

12% means 12 ml in 100 ml of water in 1 ml their is 12/100 ml of chlorine and in 60 ml it becomes 12*60/100

similarly for 8% ..8* v /100

equating both we get v=90 ml so additional water required is 90-60=30 ml

Answer 2

30 ml of water must be added to create a 8% chlorine solution

Explanation:

According to dilution law;

$C_1V_1=C_2V_2$

$C_1$ = Concentration of concentrated chlorine = 12 %

$V_1$ =Volume of concentrated chlorine = 60 ml

$C_2$ = Concentration of diluted chlorine = 8 %

$V_1$ = Volume of diluted chlorine = ?

$12\times 60=8\times V_2$

$V_2=90ml$

Thus water that must be added is = (90-60)ml=30 ml

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