Math, asked by sp4890089, 18 days ago

F 7. Evaluate the zeroes of the polynomial 2x2 - 16. (a) 272,-212 (b) 3,- (c) 4,-4 (d) 2, -2​

Answers

Answered by jash999999999
0

Answer:

2 x { }^{2}  \:  - 16 = 0 \\ 2x { }^{2}  = 16 \\ x {}^{2}   = 16 \div 2 \\ x {}^{2}  = 8 \\ x =  +  -   \sqrt{8}  \\ x =  - 2 \sqrt{2} \:  \:  \:  \:  and \:  \:  + 2 \sqrt{2}  \\  \\  \\ by \: taking \: round \: off \: and \: asper \: given \: question \: option \:  \: d \: is \: correct

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