f a 1/d^2 and d = 5 when f = 16. Find the value of f when d = 10
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Step-by-step explanation:
Given F a 1/d^2 and d = 5 when f = 16. Find the value of f when d = 10
- Now f is inversely variance with d^2
- So f = k/d^2 where k is a constant---------------1
- Or k = f x d^2
- k = 16 x 25 (since f = 16 and d = 5)
- k = 400
- Substituting k in equation 1 we get
- f = 400 / d^2
- We need to find f when d = 10, so we get
- f = 400 / 10^2
- f = 400 / 100
- f = 4
Reference link will be
https://brainly.in/question/4731518
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