Biology, asked by dubey3980, 1 year ago

F a 1000 kb fragment of dna has 10 evenly spaced and symmetric replication origins and dna polymerase moves at 1 kb per minute, how many minutes will it take to produce two daughter molecules ignoring the potential problem at the end of the linear piece of dna? assume that the 10 origins are evenly spaced from each other, none starting from the ends of the chromosome

Answers

Answered by thewordlycreature
3

The question is: If a 1,000-kilobase (kb) fragment of DNA has 10 evenly spaced and symmetric replication origins and DNA polymerase moves at 1 kb per second, how many seconds will it take to produce two daughter molecules (ignore potential problems at the ends of this linear piece of DNA)? Assume that the 10 origins are evenly spaced from each other but not from the ends of the chromosome.

A.20 B.30 C.40 D.50 E.100

Answer:

There are 10 origins of replication each with a DNA polymerase, and 100 kbp between them. So basically there are together the 10 DNA Pols moving at 1kbp per second will create two seperate 1000kbp strands within 100 seconds. So one hundred second is the correct answer to the question. There must be multiple DNA polymerase and there should be one for each origin.

Similar questions