Question

f A and B be two zeros of the quadratic polynomial 3 x^2 + 5 x + 13 then we evaluate a.1/A + 1/ B b. A^2+ B^2 c. A/ B + B/ A​

Answer 1

Answer:

x= -5+√-131 /6 , -5-√-131 /6

Step-by-step explanation:

Let, p(x) =0

3x²+5x+13 =0

=>Now,

∆=b²-4ac =(5)²-4(3)(13) =25-156 = -131 <0

(alpha,beta)

= -b±√∆ /2a = -(5)±i√-131 /2(3) = -5±i√-131 /6

alpha = -5+i√-131 /6 ; beta = -5-i√-131 /6

alpha×beta = c/a = 13/3

alpha+beta = -b/a = -5/3

=> We get,

x= -5+√-131 /6 , -5-√-131 /6