Question

f A' ∪ B=U, show by using laws of algebra of sets that A ⊂ B, where A denotes the complement of A and U is the universal set.

Answer 1

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Let A = {1, 2} B = {3, 4} and C = {5, 6}

Let A = {1, 2} B = {3, 4} and C = {5, 6}A U B = {1, 2, 3, 4} and (A U B) U C = {1, 2, 3, 4, 5, 6}

Let A = {1, 2} B = {3, 4} and C = {5, 6}A U B = {1, 2, 3, 4} and (A U B) U C = {1, 2, 3, 4, 5, 6}B U C = {3, 4, 5, 6} and A U (B U C) = {1, 2, 3, 4, 5, 6}

Let A = {1, 2} B = {3, 4} and C = {5, 6}A U B = {1, 2, 3, 4} and (A U B) U C = {1, 2, 3, 4, 5, 6}B U C = {3, 4, 5, 6} and A U (B U C) = {1, 2, 3, 4, 5, 6}Thus, the law holds true and is verified.

Answer 2

Step-by-step explanation:

show by using laws of algebra of sets that A ⊂ B, where A denotes the complement of A and U is the universal set.