f a car at rest accelerates uniformly and attains a speed of 72km/h in 10s then it covers a distance of
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the car will cover a distance of 2
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Answer:
Explanation
Here: u=0,v=72 km/hr
=72×518
=20 m/s
=10 sec
The first equation of motion is
v=u+at
20=0+a×10
⇒ v=u+at
20=0+a×10
⇒ a=2010
=2 m/s2
The second equation of motion
s=ut+12at2
=0×10+12×2×(10)2
=100
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