Math, asked by mohitdevnani75, 3 months ago

f A earns 100/3% more than B, how much percent does B earn less than A ?



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Answered by bharathsaikannan
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Answer:

like my answer if you like

Step-by-step explanation:

Well, since A is earning 33.3% more, we can take it in one of two ways.

Either you meant recurring or raw 33.3%.

If it was recurring, we take it to be 4/3 more. So we flip the fraction when flipping the subject.

So 3/4 = 75%. 100–75=25%.

Therefore, B= 25% less than A.

Or if it was raw 33.3%, we do the same, just with the fraction 1333/1000.

Flip the fraction and work it out. Then turn it into a percentage.

(1000/1333)=~75.01875468867217%

100-75.01875468867217=24.98124531132783%. So, rounded to 2sf, it would be 25%. I’ll round to 4, making it 24.98%.

There are your two answers, either 25% less or 24.98% less.

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