Question

F)
A has three times as many sweets as B. If he gives 6 sweets to B, then he has
twice as many sweets as B. How many sweets did each have initially?
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Answer 1

Answer:

A has 54 and B has 18

Step-by-step explanation:

let the number of sweets which b has be x

so A has 3x

3x-6=(x+6)*2

3x-6=2x+12

3x-2x=12+6

x=18