Question

f a house has two 60 watt bulbs lighted for 5 h, a 100Watt lamp lighted for2 h, a 50 Watt

TV running for 8 hand two electric fans working for 10 h of power of 50 Watt. Then how

many electric units are consumed for each day?​

Answer 1

Answer:

25.2 kWh

Explanation:

Energy = Power*time

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWhEnergy consumed by 40 W bulbs per day = 4∗40∗4 Wh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWhEnergy consumed by 40 W bulbs per day = 4∗40∗4 Wh = 0.64 kWh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWhEnergy consumed by 40 W bulbs per day = 4∗40∗4 Wh = 0.64 kWhTotal energy consumed per day = 0.2 + 0.64 kWh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWhEnergy consumed by 40 W bulbs per day = 4∗40∗4 Wh = 0.64 kWhTotal energy consumed per day = 0.2 + 0.64 kWh = 0.84 kWh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWhEnergy consumed by 40 W bulbs per day = 4∗40∗4 Wh = 0.64 kWhTotal energy consumed per day = 0.2 + 0.64 kWh = 0.84 kWh Therefore, the energy consumed in 30 days = 30∗0.84 kWh

Energy = Power*timeEnergy consumed by 100 W bulb per day = 2∗100 Wh = 0.2 kWhEnergy consumed by 40 W bulbs per day = 4∗40∗4 Wh = 0.64 kWhTotal energy consumed per day = 0.2 + 0.64 kWh = 0.84 kWh Therefore, the energy consumed in 30 days = 30∗0.84 kWh = 25.2 kWh

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