F all 2s are replaced by 3, then the algebraic sum of all the numbers from 1 to 200(both inclusive) is equal to
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sum of numbers till 200 =n(n+1)÷2= 200×201÷2=20100
number of times 2 are used (ones place=20+ tens place= 20 +hundreds place 1)=41 which are replaced by 3 so sum of numbers = is 20100+20+200+100= 20420
number of times 2 are used (ones place=20+ tens place= 20 +hundreds place 1)=41 which are replaced by 3 so sum of numbers = is 20100+20+200+100= 20420
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