f) An object is thrown vertically upward with a velocity of 19.6 m/ s. Find how high it will reach before falling down?
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Answer:
19.6 m
Explanation:
Answered by
0
Answer:
The object will reach a height of 19.6 m before falling.
Explanation:
Final velocity of the object, v = 0
Initial velocity of the object, u = 19.6 m/s
Acceleration of the object, a = g = -9.8 m/s²
The value of g is negative since the object is moving against the direction of acceleration due to gravity.
The distance covered by the object can eb found using the 3rd equation of motion.
v² - u² = 2gS
⇒ S = (v² - u²) / 2g
= (0² - 19.6²) / (2 × -9.8)
S = 19.6 m
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