Question

f α and β are zeroes of polynomial x2–6x + k, find the value of k such that( α + β )2–2α β= 40.

Answer 1

Step-by-step explanation:

in the equation x² - 6x + k

we have ,

a = 1 ,b = -6 ,c = k

so value of x + y = - b / a ( note: here i have applied formula )

x + y = - ( - 6 ) / 1

x + y = 6

we also have to find the value of xy so

xy = c/ a

xy = k

now given us equation ,

( x + y ) ² - 2xy = 40

( 6 )² - 2 ( k ) = 40

36 - 2k = 40

36 - 40 = 2k

- 4 = 2k

k = -2

hope this helps