F and E are the points on sides AB and CD of the rectangle ABCD that AFCE is a rhombus. If AB=16, BC =12 then find the length of EF. If AB= a, BC= b then find the length of EF.
Answers
Answered by
2
answer:EF=15cm
hope it helps u
pls mark me brainliest
Attachments:
Answered by
2
Length of EF = 15 cm where F and E are the points on sides AB and CD of the rectangle ABCD that AFCE is a rhombus.AB=16, BC =12
Step-by-step explanation:
let say AF = CE = AE = CF = x ( all sides of rhombus are equal)
then BF = AB - AF = 16 - x
BC = 12
CF² = BF² + BC²
=> x² = (16-x)² + 12²
=> x² = 256 + x² - 32x + 144
=> 32x = 400
=> x = 12.5
BF = DE = 16-x = 16-12.5 = 3.5
Horizontal Distance between EF = 16 - 2*(3.5) = 9 cm
Vertical distance between EF = 12 cm ( = BC)
EF² = 9² + 12²
=> EF² = 225
=> EF = 15 cm
Length of EF = 15 cm
Learn more:
in the given figure EADF is a rectangle and ABC is a rectangle ...
https://brainly.in/question/13113906
ABCD is a rectangle. the points E, F, G and H are chosen on the ...
https://brainly.in/question/10047448
Attachments:
Similar questions