F=at+bt^-2 find diameter of a and b .t= time f= force
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F=at +bt^-2
[MLT^-2]=a[T]
a=[MLT^-3]
[MLT^-2]=b[1/T^2]
b=[ML]
diameter of a is MLT^-3 and b is ML
[MLT^-2]=a[T]
a=[MLT^-3]
[MLT^-2]=b[1/T^2]
b=[ML]
diameter of a is MLT^-3 and b is ML
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