Question

F=ax²+bt+c/d-t find the value of a,b,c,d

Answer 1

We. know dimensional. formula of

Force, F = [MLT–² ]

Distance/Displacemet, D = [ L ]

Time T = [ T ]

Since Quantities are getting added hence their dimensions should be same as that of force.

On equating

( i )

F = ax²

[ MLT–² ] = a [ L² ]

[ MLT–² ] / [ L² ] = a

[ ML–¹ T–² ] = a

( ii )

F = bt

[ MLT–² ] = b [ T² ]

[ MLT–² ] / [ T² ] = b

[ MLT–4 ] = b

( iii )

Since t is subtracted from d hence dimension of d should be same as that of time

d = [ T ]

( iv )

F = c / ( d–t )

[ MLT–² ] = c / [ T ]

[ MLT–² ] × [ T ] = c

[ MLT–¹ ] = c

Hope the solution is clear to you!!

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