Question

(f) Calculate the percentage of :
i)Oxygen and nitrogen in ammonium nitrate. [NH4NO3]
[ N = 14, H = 1, O = 16]

Answer 1

Answer:

Molecular mass of NH4NO3 = $14 + 1 × 4 + 14 + 16 × 3$

=$14 + 4 + 14 + 48$

=$18 + 62$

=$80 g$

Mass of Oxygen = 48 g

Percentage of Oxygen in AmmoniumNitrate = Mass of Oxygen / Molecular mass of NH4NO3 × 100

$=48/80×100$

$=3/5 × 100$

$=60%$%

Mass of Nitrogen = 28 g

Percentage of Nitrogen in Ammonium Nitrate $=28/80×100$

$=7/20×100$

$=7×5$

$=35%$%