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Cos²67° -sin²23°
Cos²67° - sin²(90-67)
Cos²67 -cos²67
= 0
I hope this will help you
-by ABHAY
Cos²67° - sin²(90-67)
Cos²67 -cos²67
= 0
I hope this will help you
-by ABHAY
Answered by
0
♧♧HERE IS YOUR ANSWER♧♧
Trigonometry is the study of angles and its ratios. This study prescribes the relation amongst the sides of a triangle and angles of the triangle.
There are sine, cosine, tangent, cot, sectant and cosec ratios to an angle of a triangle.
Let me tell you an interesting fact about Trigonometry.
"Triangle" > "Trigonometry"
Remember some formulae now :
sin²θ + cos²θ = 1
sec²θ - tan²θ = 1
cosec²θ - cot²θ = 1
Want to learn more!
Here it is :
sin(A + B) = sinA cosB + cosA sinB
sin(A - B) = sinA cosB - cosA sinB
cos(A + B) = cosA cosB - sinA sinB
cos(A - B) = cosA cosB + sinA sinB
SOLUTION :
Now, sin23°
= sin(90-67)°, since sin(90-θ) = cosθ
= cos67°
So,
cos²67 - sin²23
= cos²67 - cos²67
= 0
♧♧HOPE IT HELPS YOU♧♧
Trigonometry is the study of angles and its ratios. This study prescribes the relation amongst the sides of a triangle and angles of the triangle.
There are sine, cosine, tangent, cot, sectant and cosec ratios to an angle of a triangle.
Let me tell you an interesting fact about Trigonometry.
"Triangle" > "Trigonometry"
Remember some formulae now :
sin²θ + cos²θ = 1
sec²θ - tan²θ = 1
cosec²θ - cot²θ = 1
Want to learn more!
Here it is :
sin(A + B) = sinA cosB + cosA sinB
sin(A - B) = sinA cosB - cosA sinB
cos(A + B) = cosA cosB - sinA sinB
cos(A - B) = cosA cosB + sinA sinB
SOLUTION :
Now, sin23°
= sin(90-67)°, since sin(90-θ) = cosθ
= cos67°
So,
cos²67 - sin²23
= cos²67 - cos²67
= 0
♧♧HOPE IT HELPS YOU♧♧
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