Question

F Find the equation of parabola whose
vertex (-1,-2) and focus (-1,0)​

Answer 1

Answer:

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Step-by-step explanation:

The vertex and focus of parabola lie on its axis.

Points (4,−3) and (4,−1) lie on the line x=4.

So, the axis of parabola is the line x=4.

So, the equation of parabola is (x−4)2=−4a(y+1)

Distance between focus and vertex =−1−(−3)=2.

∴a=2.

So, the equation of parabola is (x−4)2=−4(2)(y+1)

⟹x2−8x+16+8y+8=0.

⟹x2−8x+8y+24=0.