Question

f find the greatest number of 6 digits which is exactly divisible by 27 45 60 and 72​

Answer 1

Answer:

Required number is 999000

Step-by-step explanation:

given numbers are 27 45 60 and 72

we have to find greatest 6 digits number which is divisible by given numbers

we first find LCM of given numbers then we find multiple of LCM which is greatest 6 digits number

27= 3×3×3

45= 5×3×3

60= 2×3×2×5

72= 2×2×2×3×3

LCM= 2×2×2×3×3×3×5

= 1080

now we find the multiple of 1080 which is largest y digits number for divisible 999999 ÷ 1080 we get 925.925

So, 925th multiple of 1080 is largest 6 digits number

i.e, 1080 × 925 = 999000

Therefore, required number is 999000

I hope this answer helps u

Answer 2

Step-by-step explanation:

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