F) Find the least number when divided by 12, 18 and 24 leaves a remainder of 6 in
each case.
G) Find the smallest number when divided by 20, 30 and 45 leaves the remainder 14, 24
and 39 respectively.
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Answer:
First we have to find the L.C.M of 12,16,24,36
L.C.M by prime factorization method
12= 2*2*3
16=2*2*2*2
24= 2*2*2*3
36= 2*2*3*3
L.C.M= 2*2*2*2*3*3 = 144
Add remainder 7 to the L.C.M = 144+7= 151
The least number which when divided by 12,16,24 and 36 leaves a remainder 7 in each case.
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