Question

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(ii) A man is 42 years old and his son is 12 years old. How many years ago was the father's
age six times that of the son?
A woman is seyen times as old as her son. After 5 years, she will be four times as old as​

Answer 1

Answer:

Let before x years, father's age was six times son's age.

Before x years their age was,

Father’s age = 42-x

Son's age = 12-x

Now, according to question,

42-x = 6*(12-x)

42-x = 72–6x

-x +6x = 72–42

5x= 30

x=6

Hence before 6 years father's age was six times son's age

We can verify also

42–6 = 36. Father's age

12–6 = 6. son's age

6*6=36

Hence the answer is 6.

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Answer 2

Answer:

18

Step-by-step explanation:

Let the number of years be x.

Therefore the age of son would be 12+x whereas the age of father would be 42+x.

And it is given that the age of father would be twice of the son(same as the age of the son be half of the age of the man), therefore,

2(12+x)=42+x

24+2x=42+x

2x−x=42−24

x=18

Hence, the number of years is 18.