Question

f is a continuous function on the real line. Given that x² + (f(x) - 2)x-13.f(x) +213-3=0. Then the
value of
$f\sqrt(3)$
is -(A) 2(root3 - 2)/root 3

(B) 2 (1-13)
(C) zero
(D) cannot be determined​

Answer 1

Step-by-step explanation:

${x}^{2} + (f(x) - 2)x - 13f(x) + 213 - 3 = 0$

${x}^{2} + (f(x) - 2)x - 13f(x) + 210 = 0$

$\frac{ { (\sqrt{3} })^{2} - 2 \sqrt{3} + 210 }{ \sqrt{3} - 13 } = f( \sqrt{3} )$

${x}^{2} - 2x + 210 + xf(x) - 13f(x) = 0$

${x}^{2} - 2x + 210 = (x - 13)f(x)$

$\frac{ {x}^{2} - 2x + 210 }{(x - 13)} = f(x)$

now put f(3^1/2)