Question

f is force a is area and d is density .Find the dimension of Young's modules​

Answer 1

Answer:

it's f/a i hope it help you

Answer 2

Answer:

Young's Modulus (Y) = Stress/Strain

So, dimensions of Y is equal to the dimensions of pressure. 

So, we can write

[Y]=[F]a[A]b[D]c     .....(i) [M1L−1T−2]=[M1L1T−2]a[L2]b[M1L−3]c 

Applying the principle of homogeneity of dimensions, we get

a+c=1;  a+2b−3c=−1 and  −2a=−2

On solving we get

a=1, b=−1 and c=0

Putting these value in (i), we get

[Y]=[F]1[A]−1[D]0    ⇒[Y]=[F]1[A]−1