Question

F is the force acting on the test charge qo, the electric field intensity E would be given by.
Select one:
Ora. E = F/go
b. E = F+qo
c. E = F-qo
Dd. E = go/F
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Answer 1

Answer:

Explanation:

as we know that E =F/q₀

It is the method for finding electric field

Answer 2

Answer:

Option A is the right option.

Explanation:

The standard way to define an electrical intensity at a place is by keeping a test charge at that place and evaluate the value of force at that point.

If the test charge (q₀) experiences a Force of magnitude F, then electric field at that point is given by,

Force per unit charge.

$E=\frac{F}{q_{0} }$

Hence, Electric field intensity is $E=\frac{F}{q_{0} }$.