f. John uses an electric iron of 1000 W for
30 minutes a day, a geyser of 2000 W
for one hour a day and 7 bulbs of power
100 W for 3 hours a day. The reading of
his electricity meter on 1 June 2016 was
3310. What will be the reading at the
end of the month. Also, calculate the
amount to be paid if the rate of one unit
is 4.
shounakpatra68:
hi
Answers
Answered by
1
Explanation:
ANSWER
Given that,
Power =1200W=1.2kWh
Time = 30 min / day × 30 days =0.5h×30= 15 h
Energy =Power×Time=1.2×15= 18kWh.
Answered by
0
Answer:
18kWh
Explanation:
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