Math, asked by fauzdardishagmailcom, 3 months ago

f LCM and HCF of two numbers is 27 and 3 respectively and one of the numbers is 27, then find another

number.

Answers

Answered by madhusudana33

1

LXH=AXB

27X3=27XB

81 =27B

B=81/27

B=3

THE OTHER NUMBER IS 3

SOLVING HCF AND LCM PROBLEM

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