Question

f log 3/4 (x2 - 10x - 10) > 0, then what is the least integer value of x?​

Answer 1

Answer:

answer is the 1 - 10 easy

$788 x - 9$

Answer 2

Given:

f log 3/4 (x² - 10x - 10) > 0.

To Find:

least integer value of x.

Solution:

Firstly, let's take the value of x as 1,

= log 3/4 (1² - 10×1 - 10).

= log 3/4 (1 - 10 - 10).

= log 3/4× (-19).

= 2.373.

This value is greater than 0,

Hence, The least integer value of x is 1.