|f log a ^ 3 =2,log b ^ 8 =3 then log a ^ b =
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Answer:
log
a
3=2⇒
loga
log3
=2⇒loga=
2
log3
[∵log
a
b=
loga
logb
]
And log
b
8=3⇒log
b
2
3
=3⇒3log
b
2=3⇒log
b
2=1[∵loga
m
=mloga]
⇒
logb
log2
=1⇒logb=log2
∴log
a
b=
loga
logb
=
log3
2log2
=
log3
log4
=log
3
4
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