f(n) = 3 cosec^2x + 2 sinx integrate the function
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Asked on December 30, 2019 by Akhil Deb
If
∫cosec 2xdx=
f(g(x))+
C,
then
THIS QUESTION HAS MULTIPLE CORRECT OPTIONS
A range
g(x)=
(−∞,∞)
B dom
g(x)=
(−∞,∞)∼
{0}
C
g ′
sec 2
D
x∈
(0,∞)
f ′
x
1
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ANSWER
cosec(2x)=
sin(2x)
1
=
2sin(x)cos(x)
1
=
2sin(x)cos
2
(x)
cosx
=
2tanx
1+tan
2
x
∫cosec(2x)dx==
∫
2tanx
1+tan
2
x
dx
Now put
tan(x)=
t⇒
dt=
sec 2
(1+
t 2
(1+
tan 2
∫
2t
1+t
2
×
1+t
2
dt
=
2
1
∫
t
dt
=
2
1
lnt+ C
=
2
1
ln(tanx)+
C
=
ln
tanx
+
C
2
1
lntan(x)
g(x)= tanx
Since, tanx is not defined at 0
So, domain of
g(x)=
(−∞,∞)−
{0}
Range of g(x) is (−∞,∞)
g ′
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