f:N →N: f(x) = 2x is A. one - one and onto B. one - one and into C. many - one and onto D. many - one and into
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f:N →N: f(x) = 2x is A. one - one and onto B. one - one and into C. many - one and onto D. many - one and into
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The function is surjective (onto) if every element of the codomain is mapped to by at least one element of the domain.
f(x)=2x
Domain of f is N
Codomain of f is N
Every element of N(codomain) is mapped to only one element in N(domain)
i.e. f(x)=f(y)
⟹2x=2y⟹x=y
Hence f is one one function
Every even element of N(codomain) has corresponding value in N(domain).
But, for any odd number in N(codomain) has no corresponding value in Ndomain.
Hence, f is not onto function.
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