Question

f one of the zeroes of the quadratic polynomial (k - 1)x2 + kx + 1 is -3, [1]
then the value of k is …….

Answer 1

Answer:

Step-by-step explanation:

P(x)=(k - 1)x2 + kx + 1

P(-3)=(k - 1)(-3)² + k(-3) + 1

9k-9-3k+1=0

6k=8

k=8/6

k=4/3