Question

f one of the zeros of the quadratic polynomial (k –1) x2 + kx + 1 is – 3, then the
value of k is a. 4/3
b. -4/3
c. 2/3

Answer 1

Answer:

(k-1)x2+kx+1

putting the value -3:

(k-1)*(-6)+(-3k)+1=0

or, -6k+6-3k+1=0

or,-9k+7=0

or,-9k=-7

or,-k=-7/9

or,k=7/9

Answer 2

Answer:

k = 4/3

Step-by-step explanation:

let second root is a .

then sum of root = a-3 = -k/k-1

product of root = -3a = 1/k-1

so after solving two variable with two equation we get k = 4/3, a= -1