Question

f) Paper of size AO has dimensions 1189 mm x 841 mm. Each
subsequent size A(n) is defined as A(n-1) cut in half parallel to its
shorter sides. Thus paper of size A1 would have dimensions 841
mm x 594 mm. Write a program to calculate and print paper size
A0, A1, A2, ... AS.​

Answer 1

Answer:

sorry bro

Explanation:

Paper of size A0 has dimensions 1189mm*841mm. Each subsequent size A(n) is defined as A(n-1) cut in half parallel to its shorter sides. write a programm to calculate and print paper sizes A0,A1,A2...A8 I am not able to write a programme in c for this. how to write it?

below is the c program

#include <stdio.h>

int main()

{

int Length=1189,Width=841, x, y;

for (x = 0; x <= 8; x++)

{

printf("A%d -> %d x %d\n", x, Length, Width);

y = Length;

Length = Width;

Width = y / 2;

}

return 0;

}

Answer 2

Answer:

//Paper size

#include <stdio.h>

int main()

{

   int A0, A1, A2, A3, A4, A5, A6, A7, A8, h = 1189, w = 841, h2, h4, h8, h16, w2, w4, w8, w16;

   char character = 'x';

   h2 = h/2;

   h4 = h/4;

   h8 = h/8;

   h16 = h/16;

   w2 = w/2;

   w4 = w/4;

   w8 = w/8;

   w16 = w/16;

   printf("A0 = %d%c%d\n", h, character, w);

   printf("A1 = %d%c%d\n", w, character, h/2);

   printf("A2 = %d%c%d\n", h/2, character, w/2);

   printf("A3 = %d%c%d\n", w/2, character, h/4);

   printf("A4 = %d%c%d\n", h/4, character, w/4);

   printf("A5 = %d%c%d\n", w/4, character, h/8);

   printf("A6 = %d%c%d\n", h/8, character, w/8);

   printf("A7 = %d%c%d\n", w/8, character, h/16);

   printf("A8 = %d%c%d\n", h/16, character, w/16);

   return 0;

}

OUPPUT;

A0 = 1189x841

A1 = 841x594

A2 = 594x420

A3 = 420x297

A4 = 297x210

A5 = 210x148

A6 = 148x105

A7 = 105x74

A8 = 74x52

SOLUTION USING BASIC CONCEPTS