f:R->R defined by f(x)=2x+3 then fof(x)= *
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Answer :
fof(x) = 4x + 9
Solution :
- Given : f : R → R , f(x) = 2x + 3
- To find : f(x) = ?
We have ;
f(x) = 2x + 3
Thus ,
=> fof(x) = f [ f(x) ]
=> fof(x) = f (2x + 3)
=> fof(x) = 2(2x + 3) + 3
=> fof(x) = 4x + 6 + 3
=> fof(x) = 4x + 9
Hence ,
fof(x) = 4x + 9
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