F:R—>R, f(x)=x³-6x²-36x+2,Determine intervals in which the given function are strictly increasing or strictly decreasing.
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Answered by
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Dear student:
Given: f:R —>R
f(x)= x³-6x²-36x+2
For determining the intervals in which f is increasing and decreasing.
Find derivative of f(x)
then see the derivative in which f is positive and negative.
If it is positive then f is increasing
And if it is negative then f is decreasing.
See the attachment.
Attachments:
![](https://hi-static.z-dn.net/files/da3/0c7a33922d1153596ae96297593d9172.jpg)
Answered by
1
In the attachment I have answered this problem.
Concept:
If the derivative of f(x) is positive for all values of x in interval I then f(x) is strictly increasing in I.
If the derivative of f(x) is negative for all values of x in interval I then f(x) is strictly decreasing in I.
See the attachment for detailed solution.
Attachments:
![](https://hi-static.z-dn.net/files/da9/402ad0b38376993c59fde107474e5d22.jpg)
![](https://hi-static.z-dn.net/files/d70/1ce77db41152407241bd9c91537edbd3.jpg)
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