Question

f = (S^2+2s-6)N. find work done by
force
f from
S = 2 m to s = 4 m​

Answer 1

Answer:

$\\\tt \dfrac{56}{3} J$

Explanation:

$\\\tt F = ( {s}^{2} + 2s - 6) N$

Since

W = F.dr

To get work we gotta integrate both sides here from 2 to 4 (since units balance themseleves out here no need of conversion is required)

\\\tt

$\\\tt \int_2 ^4 ( {s}^{2} + 2s - 6)$

$\\\tt [ \frac{ {s}^{3} }{3} + \frac{ 2{s}^{2} }{2} - 6x ]_2^4 \\ = \tt [ \frac{ {s}^{3} }{3} + {s}^{2} - 6x ]_2^4$

$\\\tt (\dfrac{64}{3} + 16 - 24) - (\dfrac{8}{3} + 4 - 12) \\\tt = \dfrac{56}{3} + 12 - 12 \\ \\\tt = \dfrac{56}{3}$