f sin A =1/√2
and cot B = 1 then show that sin(A+B)=1
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it's just simple
see the following steps
Step-by-step explanation:
Sin A = 1/√2
Sin A= Sin 45
this gives, A= 45
similarly
Cot B = Cot 1
Cot B = cot 45
this gives, B = 45
sub A nd B value in que
A= 45 nd B = 45
Sin (45+45) = Sin (90)
we know that
sin90 =1
therefore sin (A+B)=1
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