Question

f sin (A-B) = 1

2

, cos (A+ B) = 1

2

, 00< A + B ≤ 900

, A > B, find A and B.​

Answer 1

Answer:

HERE WE GO

Step-by-step explanation:

SEECAREFULLY PLEASE

Cos(A+B) = 1/2

Cos(A+B) = 1/2⇒cos (A+B) = cos(60)  (as 0<A+B<90)

Cos(A+B) = 1/2⇒cos (A+B) = cos(60)  (as 0<A+B<90)⇒A+B = 60

Cos(A+B) = 1/2⇒cos (A+B) = cos(60)  (as 0<A+B<90)⇒A+B = 60sin(A-B) = 1/2

Cos(A+B) = 1/2⇒cos (A+B) = cos(60)  (as 0<A+B<90)⇒A+B = 60sin(A-B) = 1/2⇒sin(A-B) = sin(30) or sin (150)

Cos(A+B) = 1/2⇒cos (A+B) = cos(60)  (as 0<A+B<90)⇒A+B = 60sin(A-B) = 1/2⇒sin(A-B) = sin(30) or sin (150)⇒A-B = 30 or 150

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Case:1

Case:1A - B = 30

Case:1A - B = 30A + B = 60

Case:1A - B = 30A + B = 60Solving we get, A = 45 and B = 15

Case:1A - B = 30A + B = 60Solving we get, A = 45 and B = 15A>B is satisfied.

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Case:2

Case:2A - B = 150

Case:2A - B = 150A + B = 60

Case:2A - B = 150A + B = 60Solving, we get A = 105, B = -45

Case:2A - B = 150A + B = 60Solving, we get A = 105, B = -45A>B is satisfied.

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So the value of A can be 45 or 105 OK GUY!

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Answer 2

Here is your answer mate

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