F×t=m(v-u) is dimensionally correct or not show
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Answer:
"The dimensional formula of at is [M0LT-2][T]=[M0LT-1]. Here the dimensions of every term in the given physical relation are the same , hence the given phyical relation is dimensionally correct."
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Answer:
F = ma ------{i}
v = u +at
at = v - u
a = v - u / t -----{ii}
from {i} and {ii}
F = m(v - u / t)
Ft = m(v - u)
M¹L¹T⁻² × M⁰L⁰T¹ = M¹(M⁰L¹T⁻¹ - M⁰L¹T⁻¹)
M¹⁺⁰ L¹⁺⁰ T⁻²⁺¹ = M¹ L⁰T⁰× M⁰L¹T⁻¹
M¹L¹T⁻¹ = M¹⁺⁰ L¹⁺⁰ T⁻¹⁺⁰
M¹L¹T⁻¹ = M¹L¹T⁻¹
LHS = RHS
Hence proved
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