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Answers
10.)
length = l = 12m
Area of wall × rate per sq m = 340.20 rupees
Area of wall = 340.20 ÷ 1.35
Area if wall = 252 m²
Area of floor × rate per sq m = 91.80
Area of floor × 0.85 = 91.80
Area of floor = 91.80 ÷ 0.85
Area of floor = 108m²
l × b = 108m²
20 × b = 108
b = 108 ÷ 20 = 5.4m
b = 5.4
Total Area of room inside = 2 Area of wall + 2 Area of floor + 2(5.4 × h)
= (2 × 252) + (2 × 108)
= 504 + 216 = (720 + 10.8h)m²
Total Area of room inside = (720 + 10.8)m² = TSA(cuboid)
T.S.A(cuboid) = 2lb + 2lh + 2hb
720 + 10.8h = 2 (20 × 5.4) + 2(20 × h) + 2(h × 5.4)
720 + 10.8h = 216 + 40h + 10.8h
720 - 216 = 40h
504 = 40h
504/40 = h
h = 12.6 m
__________________________
12.)
let common multiple be x
•°• 3x:2x:x
l =3x, b = 2x, h =x
TSAof cuboid = 2lb + 2lh + 2hb
8800 = 2(3x × 2x) + 2(3x × x) + 2(x × 2x)
8800 = 2(6x²) + 2(3x²) + 2(2x²)
8800 = 12x² + 6x² + 4x²
8800 = 22x²
8800/22 = x²
400 = x²
√400 = x
20 = x
Dimentions: 3x = 3 × 20 = 60
2x = 2 × 20 = 40
x = 20
60,40,20 are the dimentions of cuboid
Answer:
hmm @MissLover thanku for
following me ( ╹▽╹ )
Step-by-step explanation:
1) Let the length of room = l = 12 m
breadth of room = b m
height of room = h m
Cost of matting the floor @ Re. 0.85 per m^2 = Rs. 91.80
floor area = 91.80 / 0.85 = 108 m^2
⇒ l * b = 108
⇒ 12 * b = 108
⇒ b = 108/12
⇒ b = 9 m
cost of papering wall @ Rs. 1.35 per m^2 = Rs. 340.20
wall area is the lateral surface area.
wall area = lateral surface area = 340.20 / 1.35 = 252 m^2
⇒ 2h(l+b) = 252
⇒ 2h(12+9) = 252
⇒ 2h*21 = 252
⇒ h = 252/(2*21)
⇒ h = 6 m
Height of room is 6m.
2) The volume of the cuboid = 3x*2x*x = 384, or
6x^3 = 384
x^3 = 384/6 = 64
x= 64^(1/3) = 4
So the cuboid is 12 cm x 8 cm x 4 cm/
The total surface of the cuboid = 2 (12*8 + 8*4 + 4*12)
= 2(96 + 32 + 48)
= 2*176
= 352 sq cm. Answer