Question

f tan = 5/12 and is acute. Find the value of sin and cot ​

Answer 1

Answer:

Step-by-step explanation:

we know that tanФ=perpendicular/base=5/12

so hypotenuse²=perpendicular²+base²

⇒hypotenuse²=5²+12²=25+144=169

so hypotenuse=root of 169=13

so we know that sinФ=perpendicular/hypotenuse=5/13

also,cosФ=base/hypotenuse=12/13

if the second subquestion was cotФ,then cotФ=base/perpendicular=12/5

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