Physics, asked by krantHi3020, 9 months ago

F the actual requirements of a house is 1200 wh & dod is 50% then how much energy we need to store in the battery? 2400 kwh 2000 wh 2.4 kwh 1200 wh

Answers

Answered by VaishnaviMohan
4

Answer:

So you need 1200 / 250 = 4.8 hours of bright sunlight. A single solar panel of 280 watts will do the work for you. There are other solar panels with various power ratings you can install to charge your batteries such as 100 watts, 150 watts, 235 watts, 250 watts and many more.

Explanation:

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Answered by Jasleen0599
4

Given:

The actual requirement of energy = 1200 Wh

Depth of discharge, dod = 50 %

To Find:

The energy that should be stored in the battery.

Calculation:

- Let the energy that should be stored in the battery be X.

- According to the condition:

50% of X = 1200

⇒ 50/100 × X = 1200

⇒ X = 1200 × 100/50

⇒ X = 2400 Wh = 2.4 KWh

- So, the correct answer is option (3) 2.4 KWh.

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