Question

f the angle between the incident ray and the normal to the plane of the mirror is 40∘, the angle between the incident ray and the reflected ray will be

Answer 1

${\large{\bold{\rm{\underline{Required \; Solution}}}}}$

If the angle between the incident ray and the normal to the plane of the mirror is 40°, the angle between the incident ray and the reflected ray will be

${\large{\bold{\rm{\underline{Given \: that}}}}}$

• The angle between the incident ray and the normal to the plane of the mirror is 40°

${\large{\bold{\rm{\underline{To \: find}}}}}$

• The angle between the incident ray and the reflected ray will be how much?

${\large{\bold{\rm{\underline{Solution}}}}}$

• The angle between the incident ray and the reflected ray will be 100

${\large{\bold{\rm{\underline{Full \; Solution}}}}}$

~ As it's already given that the angle between the incident ray and the normal to the plane of the mirror is 40 degree. Henceforth,

→ Angle of incidence = 90° - Angle between incident ray and mirror

→ Angle of incidence = 90 - 40

→ Angle of incidence = 50°

~ Using law of reflection,

→ Angle of incidence is always equal to angle of reflection

→ Angle of incidence = Angle of reflection

→ ∠i = ∠r

→ 50 = 50

→ 50° = 50°

~ Now let's find the angle between the incident ray and the reflected ray..!

→ Angle of incidence + Angle of reflection

→ ∠i + ∠r

→ 50 + 50

→ 50° + 50°

→ 100°