f the angles of a quadrilateral are in A.P with common difference 10 then the sum of angles is
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Step-by-step explanation:
Let one of the angle is a
So there angles are a+10,a+20,a+30
a+a+10+a+20+a+30=360
4a+60=360
4a=300
∴a=75
First angle=75∘
Second angle=75+10=85∘
Third angle=85+10=95∘
Forth angle=95+10=105∘
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