Question

F the coordinates of point a are (2,2) and the coordinates of point b are (0, -2), what is the equation of the perpendicular bisector of line segment ab1

Answer 1

Given Points are a (2,2) b (0,-2)

Midpoint of ab is (1,0)

Slope of ab is

$\frac{ - 2 - 2}{0 - 2} = \frac{ - 4}{ - 2} = 2$

Slope of Perpendicular Bisector is

$= \frac{ - 1}{slope \: of \: ab} \\ = \frac{ -1}{2}$

Equation of Perpendicular Bisector is

$y - 0 = ( \frac{ - 1}{2} )(x - 1) \\ 2y = - x + 1 \\ x + 2y - 1 = 0$

Hence equation of Perpendicular Bisector is

$x + 2y - 1 = 0$

Hope it helped.....

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