Question

f the KE of an object changes from 10 J to 35 J in 15s :
Select answers
A
Total work done on the object in 15 sec is 15 Joule
B
Total work done on the object in 15 sec is 25 Joule
C
Average power delivered to the object is 5/3 watt
D
Average power delivered to the object is 4/3 watt

Answer 1

Explanation:

Total work done on the object in 15 sec is 25 joule

Answer 2

Average power delivered to the object is 5/3 watt and option (C) is correct.

Explanation:

Given:

The KE of an object changes from 10 J to 35 J in 15 sec.

To Find:

Average power delivered to the object.

Concept Used:

Average power is the total energy consumed divided by the total time taken.

$Average Power=\frac{Energy\ Consumed }{Time \ taken}$    --------- formula no.01.

The energy possessed by an object due to its motion is called kinetic energy of that object.

Solution:

As given,The KE of an object changes from 10 J to 35 J in 15 sec.

Energy Consumed $=35-15 \ Joule$

                                $=25 \ Joule$

Time taken $=15 sec.$

$Average Power=\frac{25 }{15} =\frac{5}{3}$

Thus,average power delivered to the object is 5/3 watt and option (C) is correct.

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