f the sum of zeroes of the quadratic polynomial x2+(a+1)x+b are 2 and -3 then a and b are
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Answer:
-3
Step-by-step explanation:
if 2 is 0 of polynomial then
p(x)= 2x + (a+1)x+b=0
p(2) =2x2 + (a+1)2+b =0
". = 4+2a+2 +b =0
". =6+2a+b=0
". = 2a+b= -6
". =a+b =-6/2
". =a+b =-3
if -3 is 0 of polynomial then
p(-3)=2×-3+(a+1) -3+b =0
". =-6-3a-3+b=0
". =-9-3a+b =0
". =-3a+b=9
". =a+b=9/-3
". =a+b =-3
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